number system Model Questions & Answers, Practice Test for ssc chsl tier 1 2023
ssc chsl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Powers Surds & Indices
Ratio Proportion & Partnership
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
When 96 is added to a $N^2$ , it gives another perfect square. If N is a natural no., how many distinct values of N are possible?
Answer: (b)
$N^2 + 96 = P^2$ , or, 96 = $P^2 – N^2$.
Now factorize 96 and equate it with (P + N) (P – N).
If 653xy is divisible by 80 then the value of x + y is
Answer: (d)
Since 80 = 8 × 10 or 80 = 16 × 5
Thus y (i.e., unit digit) must be zero.
∴ 653xy = 653x0, where 653x0 must be divisible by 16 or 653x is divisible by 8.
Thus the last 3-digit number 53x will be divisible by 8.
Hence, at x = 6, we get the required result.
∴ x + y = 6 + 0 = 6
Two numbers when divided by a certain divisor leave the remainders 4375 and 2986 respectively; but when the sum of the two numbers be divided by the same divisor, the remainder is 2361. The divisor is
Answer: (c)
Required Divisor = (sum of remainders)
– Remainder when sum is divided
= [ 4375 + 2986] – 2361 = 5000
The sum of prime numbers that are greater than 60, but less than 70 is
Answer: (c)
Sum of prime numbers that are greater than 60, but less than 70 is
61 + 67 = 128
ssc chsl tier 1 2023 IMPORTANT QUESTION AND ANSWERS
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